This example will demonstrate how to calculate the compressibility of real gas in order to determine gas density and specific gravity at a specific condition.

**Calculate the following based on the given condition:**

1) Density of this gas under the reservoir conditions of 7,500psia and 220ºF,

2) Specific gravity of the gas.

Gas component is shown in Table 1

Average density of air = 28.96 lb/cu-ft

## Solution

**Determine critical pressure and temperature of gas mixtures using Kay’s rule**

**Note: **critical pressure and temperature can be found from this link – http://www.drillingformulas.com/determine-compressibility-of-gases/

Pc’ = Σyipci = 660.5 psia

Tc’ = ΣyiTci = -46.2 F = -46.2 +460 F = 413.8 R

**Calculate Tr and Pr**

Tr = T ÷Tc

Tr = (220+460) ÷ (-46.2+460)

Tr = 1.64

**Note: **temperature must be in Rankin.

Rankin = Fahrenheit + 460

For the critical temperature calculation, it can be converted the critical temperature from F to R before calculating Tc’. This will still give the same result.

Pr = P ÷ Pc

Pr = 7500 ÷ 660.5 = 11.4

**Read the compressibility factor (z) from the chart.**

z = 1.22

**Calculate average molar mass**

Average Molar Mass = Σyi×Mi = 22.1 lb

- Calculate density of gas from the equation below;

Gas Density = 18.6 lb/cu-ft

- Calculate gas specific gravity from the equation below;

SG = Gas Density ÷ Air Density

SG = 18.6 ÷ 28.96

SG = 0.64

**Summary:**

The answers for this answer are listed below;

Gas Density = 18.6 lb/cu-ft

SG = 0.64

We wish that this example will help you understand to determine z-factor and use it to calculate any related information.

**References**