This article demonstrates how to design the well trajectory in J-shape from the surface location to the required target depth (TD).

**Information Given**

- The surface location coordinate of Well-A is 6,543,065.00N 416,695.00E and the target is located at 6,542,213.00N 415,456.00E and the UTM zone is 31N.

- Kick off depth = 4,200’MD/4,200’TVD
- Planned build up rate = 2 degree/100 ft
- Well profile = J-profile (build and hold)

The surface location coordinate of Well-A is 6,543,065.00N 416,695.00E and the target is located at 6,542,213.00N 415,456.00E and the UTM zone is 31N. Therefore, the surface and the target for Well-A can be illustrated is Figure 1.

**Distance from Surface Location to Target**

ΔN = 6,542,213.00 – 6,543,065.00 = – 852 m

ΔE = 415,456.00 – 416,695.00 = -1,239 m

Map Distance = 1503.671 m

**True Distance**

This distance must be applied the scale factor in order to get the true distance.

True Distance (m) = Map Distance ÷ scale factor

True Distance (m) = 1503.671 ÷ 0.999685 = 1504.144 m

Convert from meter to feet

True Distance (ft) = True Distance (m) x 3.281

True Distance (ft) = 1504.144 x 3.281

True Distance (ft) = 4934.86 ft

The true distance is the horizontal displacement referencing from surface location to the target.

**Target Azimuth**

The target in reference to the surface location is located in 3rd quadrant; therefore the target azimuth is calculated by the following relationship;

Target AZI = 180 + tan-1(ΔE÷ΔN)

Target AZI = 180 + tan-1((-1,239) ÷ (-852))

Target AZI = 235.486 degree

**Directional Plan and Calculation**

In order to design well trajectory for this well, the illustration (Figure 3) is made to determine all required parameters.

**Calculations**

Radius build (ft) = (180 ÷ ϖ) × (100 ÷2)

Radius build (ft) = 2,864.79 ft

**a = TVDtarget – TVDkop**

a = 9,500- 4,200 = 5,300 ft

**b = Horizontal Displacement to Target – Radius Build**

b = 4,934.86 – 2,864.79= 2070.07 ft

**c = (a^2 + b^2)^1/2**

c = (5,300^2 + 2,070.07^2)^1/2 = 5,689.92 ft

**d= (c^2 – e^2)^1/2**

d= (5,689.92^2 – 2,864.79^2)^1/2 = 4916.11 ft

**e = Radius build**

e = 2,864.79 ft (Radius build)

**f = g ÷ cos(θ1)**

f = 750÷ cos(51.565) = 1,206.52 ft

**g = Planned Depth TVD– Target Depth TVD**

g = 10,250 – 9,500 = 750 ft

**h = g × tan(θ1)**

h = 750 × tan(51.565) = 945.09 ft

**θ1 = 180- ?1- α1**

θ1 = 180 – 59.769 – 68.665 = 51.565 degree

**θ2 = 90- θ1**

θ2 = 90- 51.565 = 38.435 degree

**Distance build (ft) = Change in Inclination ÷ Build Rate**

Inclination increases from 0 degree to 51.57 degree at the end of build

Distance build = 51.57 degree ÷ (2 degree/100ft) = 2578.27 ft

**Measured Depth at End of Build = Kick of Depth + Distance Build**

Measured Depth at End of Build = 4,200 + 2,578.27 = 6,778.27 ft MD

**TVD at End of Build = Kick of Depth TVD + Radius of Build x sin (θ1)**

TVD at End of Build = 4,200 + 2864.79x sin (51.57) = 6,444.04 ft TVD

**Horizontal departure at EOB = Radius Build × (1- cos(θ1))**

Horizontal departure at EOB = 2864.79x × (1- cos(51.57)) = 1083.98 ft

**Horizontal Departure at TD = Horizontal Departure at Target + h**

Horizontal Departure at TD = 4,934.86 + 945.05 = 5879.91 ft

Figure 4 illustrates all calculated parameters for Well-A

**North-South and East-West Calculation**

Since there is no change in Azimuth direction, North-South and East-West can be calculated by the following equations

**North-South = Horizontal Departure x cos (Wellbore Azimuth)**

East-West = Horizontal Departure x sin (Wellbore Azimuth)

**North-South and East-West at Kick Off Point (KOP)**

At KOP, there is not horizontal departure so North-South and East-West direction are 0.

**North-South and East-West at End of Build (EOB)**

North-South = Horizontal Departure at EOB x cos (Wellbore Azimuth)

North-South = 1083.98x cos (235.49) = -614.20 ft

East-West = Horizontal Departure at EOB x sin (Wellbore Azimuth)

East-West = 1083.98 x sin (235.49) = -893.18 ft

**North-South and East-West at Target**

North-South = Horizontal Departure at Target x cos (Wellbore Azimuth)

North-South = 4934.86 x cos (235.49) = -2,796.16 ft

East-West = Horizontal Departure at Target x sin (Wellbore Azimuth)

East-West = 4934.86 x sin (235.49) = -4,066.24 ft

**North-South and East-West at Total Depth (TD)**

North-South = Horizontal Departure at TD x cos (Wellbore Azimuth)

North-South = 5879.95x cos (235.49) = -3,331.66ft

East-West = Horizontal Departure at TD x sin (Wellbore Azimuth)

East-West = 5879.95x sin (235.49) = -4,844.98ft

Figure 5 shows the plan view of Well-A and Table 1 demonstrates all critical points.

**Calculation Summary**

Well-A is planned for 2-D well design with a J-shape trajectory plan. The well will be drilled vertically to 4,100’ MD/4,100’ TVD. Then, the kick off starts at 4,200’ MD/4,200’ TVD (100 ft below 16” shoe) in a firm shale zone and the designed build up rate is 2 degree/100 ft. End of build depth is 6,778’MD/6,444’TVD. The target depth is 11,694’MD/9,500’ TVD KRB and the target depth of the well is 12,901’MD/10,250’ TVD KRB.

**Reference** – https://www.linkedin.com/pulse/well-trajectory-j-profile-example-directional-suwat-pongtepupathum

Hello,

Thanks for this. Please, what would the azimuth be if the target reference is in the 1st, 2nd or 4th quadrant?

It is in the 3rd quadrant.