This topic will teach you how to determine water requirement (gal/sack) and yield of cement (gallon/sack) as per cement slurry program.
The cement formula given from town is listed below:
Class G cement
35% Silica sand (35% by weight of cement)
0.2 gps of chemical A
0.6 gps of chemical B
Required cement density = 15.5 ppg
The absolute volume of each material is listed below:
Class G cement = 0.0382 gal/lb
Silica sand = 0.0456 gal/lb
Chemical A = 0.0974 gal/lb
Chemical B = 0.103 gal/lb
Determine requirement (gal/sack), yield of cement
We still use the same concept as previous calculation:
Volume = Weight x Absolute Volume
Volume in gal/sack
Weight in lb/sack
Absolute volume in gal/lb
We can create table showing each component of cement slurry as shown below:
|Weight (lb/sack)||Absolute volume (gal/lb)||Volume (Gal/sack)|
|1 sack of class G cement||94||0.0382||94 x 0.0382 = 3.591|
|35% Silica sand||0.35 x 94 = 32.9||0.0456||32.9 x 0.0456 = 1.5|
|Chemical A||0.2 ÷ 0.0974 = 2.053||0.0974||2.053 x 0.0974 = 0.2|
|Chemical B||0.6 ÷ 0.103 = 5.825||0.103||5.825 x 0.103 = 0.6|
|Water||8.33 x k||1/8.33||k|
where; k is the variable that must be solved.
Total weight per sack of cement =94+32.9+1.0267+5.825+8.33k = 133.7517 + 8.33k
Total volume of cement slurry per sack of cement = 3.591+1.5+0.2+0.6+k = 5.891 + k
Cement Density = Total weight per sack of cement ÷ Total volume of cement slurry
15.5 = (133.7517 + 8.33k) ÷ (5.891 + k)
Solve for k: k = 5.92
After k is solved, you will get water requirement and cement yield.
The water requirement is 5.92 gal/sack.
Yield of cement = 5.891 + 5.92 = 11.811 gal/sack
Ps: I did not give you the product name in this topic or anything related to any cementing companies because I want you to understand the calculation concept. If you understand the concept, everything will be good.