This topic will demonstrate how to determine optimum drilling flow rate for both drilling hydraulic optimization methods (the maximum hydraulic horse power and the maximum impact force). If you don’t know the equations, please read this article first, Determine Optimum Drilling Flow Rate for Basic System – Drilling Hydraulics.

The information is listed below:

Hole size = 8.5 inch

Depth In = 2,000 ft

Depth out = 6,000 ft

**Mud properties at starting point**

Mud weight = 9.2 ppg

PV = 13

YP = 10

**Mud properties at TD**

Mud weight = 9.5 ppg

PV = 14

YP = 11

Drill pipe = 5”

Drill pipe ID = 4.2”

Drill pipe tool joint = 6.5”

Drill pipe tool joint ID = 3.5

Drill collar = 6-3/4”

Drill collar ID = 3-1/2”

Drill collar length = 800 ft

Coefficient of surface equipment = 5

Pump Capacity with 6” liner, Triplex pump:

Max flow rate = 900 gpm

Max Pressure = 4500 psi

The best optimization point is at the end so this calculation will be based on **Drilling Hydraulics Optimized at the End of the Run.**

**Coefficient for drill pipe and tool joint**

Where;

Cpb = coefficient through inside of pipe and tool joint

Ditj = internal diameter of tool joint, inch

Didp = internal diameter of drill pipe, inch

Cpb = 0.006243486

**Coefficient of Annulus around Drill Pipe and Tool Joint**

Where:

Cpa = coefficient for the annulus of pipe

Dh = hole diameter, inch

Dp = outside diameter of drill pipe, inch

Dj = outside diameter of tool joint, inch

B = a parameter which takes into account the difference between Q^{1.86} and Q^{2}. You can just simply select “B” value from the following table.

Cpa = 0.003082686

**Total pressure loss coefficient for drill pipe and tool joint**

Cp = Cpb + Cpa

Cp = 0.009326172

**Coefficient for drill collar**

Inside of drill collar

Where;

Ccb = coefficient through inside of drill collar

Didc = internal diameter of drill collar, inch

Ccb = 0.016337

Annulus of drill collar

Where:

Cca = coefficient for the annulus of drill collar

Dh = hole diameter, inch

Dc = outside diameter of drill collar, inch

B = a parameter which takes into account the difference between Q^{1.86} and Q^{2}

Cca = 0.016559829

**Total pressure loss coefficient for drill collar**

Cc = Ccb + Cca

Cc = 0.032896

**Coefficient for surface equipment**

Cse = 5

**Viscosity Correction Factor**

Vf = (15÷9.5)0.14

Vf= 1.055788

**Determine optimum flow rate**

**Maximum Hydraulic Horsepower**

Q = 702 gpm

**Maximum Impact Force**

Q = 868 gpm

The pump can deliver the maximum flow rate of 900 gpm therefore we can optimize both Maximum Hydraulic Horsepower and Maximum Impact Force.

**Reference: Drilling Hydraulic Books**

Hi,

Thanks for your perfect explanation.

I would be appreciated if you answer my question. What is the major reason to use HHP optimization or IF?!

Regards

The major reasons are hole cleaning and hydraulic power transfer to the bottom hole.